Introduction to entrance exam for college math:
Entrance exam for college evaluates high school students, general educational improvement and their ability to complete college-level work. SAT exam is one of the entrance exams for college math. It is used to find out skills in math, reading comprehension and vocabulary of the students planning to attend college. Now, we are going to see some of the problems on entrance exam for college math.
Entrance Exam for College Math Solved Problems:
Example problem 1:
Solve the quadratic equation by factoring method: x2 - 143x + 142 = 0.
a) 1, 142
b) 1, 132
c) 1, 122
d) 1, 112
Solution:
The given quadratic equation is x^2 - 143x + 142 = 0
Here a = coefficient of x2 = 1
b = coefficient of x = -143
c = constant term = 142
We find a × c = 1 × 142 = 142 = -1 * -142, a + c = (-1) + (-142) = -143 = b.
By splitting the middle term, we get
x2 - 143x + 142 = 0
x2 - 1x - 142x + 142 = 0
x(x - 1) - 142(x - 1) = 0
(x - 1) (x - 142) = 0
x = 1, x = 142
So, the option a is the correct answer.
So, the answer is x = 1, 142. Having problem with word problems in algebra keep reading my upcoming posts, i will try to help you.
Additional Solved Problems-entrance Exam for College Math:
Example problem 2:
Solve the following simultaneous equations using substitution method:
9x – y = 18 ----------Equation (1)
1x + y = 22--------------Equation (2)
a) (2, 25)
b) (3, 27)
c) (5, 27)
d) (4, 18)
Solution:
Step 1: Let us consider the Equation (1)
9x – y = 18
Subtract 9x on both sides of the equation
9x – y –9x = 18 – 9x
-y = -9x + 18
y = 9x - 18---------Equation (3)
Step 2: Substitute the value of y in Equation (2). We get
1x + y = 22
1x + (9x – 18) = 22
10x – 18 = 22
Add 18 on both sides of the equation
10x – 18 + 18 = 22 + 18
10x = 40
Divide by 10 on both sides of the equation
`(10x) / 10 = 40 / 10`
x = 4
Step 3: Substituting this value of x in Equation (3), we get
y = 9x – 18
y = 36 – 18
y = 18
So, the option d is the correct answer.
So, the answer is (4, 18).
Entrance exam for college evaluates high school students, general educational improvement and their ability to complete college-level work. SAT exam is one of the entrance exams for college math. It is used to find out skills in math, reading comprehension and vocabulary of the students planning to attend college. Now, we are going to see some of the problems on entrance exam for college math.
Entrance Exam for College Math Solved Problems:
Example problem 1:
Solve the quadratic equation by factoring method: x2 - 143x + 142 = 0.
a) 1, 142
b) 1, 132
c) 1, 122
d) 1, 112
Solution:
The given quadratic equation is x^2 - 143x + 142 = 0
Here a = coefficient of x2 = 1
b = coefficient of x = -143
c = constant term = 142
We find a × c = 1 × 142 = 142 = -1 * -142, a + c = (-1) + (-142) = -143 = b.
By splitting the middle term, we get
x2 - 143x + 142 = 0
x2 - 1x - 142x + 142 = 0
x(x - 1) - 142(x - 1) = 0
(x - 1) (x - 142) = 0
x = 1, x = 142
So, the option a is the correct answer.
So, the answer is x = 1, 142. Having problem with word problems in algebra keep reading my upcoming posts, i will try to help you.
Additional Solved Problems-entrance Exam for College Math:
Example problem 2:
Solve the following simultaneous equations using substitution method:
9x – y = 18 ----------Equation (1)
1x + y = 22--------------Equation (2)
a) (2, 25)
b) (3, 27)
c) (5, 27)
d) (4, 18)
Solution:
Step 1: Let us consider the Equation (1)
9x – y = 18
Subtract 9x on both sides of the equation
9x – y –9x = 18 – 9x
-y = -9x + 18
y = 9x - 18---------Equation (3)
Step 2: Substitute the value of y in Equation (2). We get
1x + y = 22
1x + (9x – 18) = 22
10x – 18 = 22
Add 18 on both sides of the equation
10x – 18 + 18 = 22 + 18
10x = 40
Divide by 10 on both sides of the equation
`(10x) / 10 = 40 / 10`
x = 4
Step 3: Substituting this value of x in Equation (3), we get
y = 9x – 18
y = 36 – 18
y = 18
So, the option d is the correct answer.
So, the answer is (4, 18).
